When you said "loop d loop" I thought you ment he was going to try two loops in succession... that would be rad. I don't see what all the hype is about one loop though, it's already been done long ago.
actually cowan did it in one of the new world disorders and it was also done at the freeze ride. but now that it has been done in the UK it is has now officialy "been done"
mg == mv^2/r
==> g == v^2/r
==> sqrt(r*g) == v
substitute r = 1.8m, g = 9.8m/s^2 and we get 4.2 m/s, or 9.5 mph. so we have to be going 9.5 mph at the top of the loop. how fast must we be going at the bottom of the loop then? add in potential energy:
KEatstart == KEattop + PE
1/2 mv^2 == 1/2 m(4.2m/s)^2 + mgh
==> v^2 == (4.2m/s)^2 + 2gh
substitute g = 9.8 m/s^2, h = 3.6m and we get, ignoring units for a second:
==> v^2 == 17.64 + 70.56 == 88.2
==> v == 9.4 m/s, or 21mph.
I couldn't be arsed to write out my maths, did it on the back of an envelope - first time I've done anything like that for about 5 years so was pleased I could remember how to do it
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