[COmtbiker12]

I need some help with this retarded Algebra II crap. My teacher didn't explain this very well and the example in the book is sh1t. Here's the problems, they deal with combinations...


Alright, out of 52 cards, what are the combinations you can have with a 5 card hand, and all of them being face cards (K/Q/J). Please show steps.



Same as previous, except the cards are 4 Aces and 1 other card....



I have no idea how the hell to do this so help would be appreciated.

 

[SkaredShtles]

I need some help with this retarded Algebra II crap. My teacher didn't explain this very well and the example in the book is sh1t. Here's the problems, they deal with combinations...


Alright, out of 52 cards, what are the combinations you can have with a 5 card hand, and all of them being face cards (K/Q/J). Please show steps.



Same as previous, except the cards are 4 Aces and 1 other card....



I have no idea how the hell to do this so help would be appreciated.

Ummmmmm.......... it's called *homework* and you're actually supposed to figure it out on your own.

-S.S.-

 

[DHracer1067]

well you cant expect someone to do it if the teacher is just like here do this.

 

[JMAC]

I need some help with this retarded Algebra II crap. My teacher didn't explain this very well and the example in the book is sh1t. Here's the problems, they deal with combinations...


Alright, out of 52 cards, what are the combinations you can have with a 5 card hand, and all of them being face cards (K/Q/J). Please show steps.



Same as previous, except the cards are 4 Aces and 1 other card....



I have no idea how the hell to do this so help would be appreciated.

What grade are you in? and I would help but I'm doing calculus for the second time so I have my own hmwk to do.

 

[COmtbiker12]

What grade are you in? and I would help but I'm doing calculus for the second time so I have my own hmwk to do.

I'm in 10th. Thanks for the suggestion S.S. but unfortunately when the teacher just rambles on and you run out of time before you can ask how to do it, it doesn't help much, especially when the assignment's due tomorrow.

 

[Smelly]

wouldn't the second one be 48 combos? 52 cards-4 aces= 48 cards left, so that's 48 cards that could potentially be the 5th card.
as for the first, i've always sucked at math.

 

[SkaredShtles]

I'm in 10th. Thanks for the suggestion S.S. but unfortunately when the teacher just rambles on and you run out of time before you can ask how to do it, it doesn't help much, especially when the assignment's due tomorrow.

Ask your parents......... they should be able to figure it out with the explanation in the book.

-S.S.-

 

[ALEXIS_DH]

.well, i think it goes like this.

there are 52 cards. you only use K,Q,J.
that means only 3 cards from each maze.

total 12 cards from which you can do the combination.
now, the part for you.
what are the combinations you can do with those 12 cards in a 5 card hand?

 

[-dustin]

What grade are you in? and I would help but I'm doing calculus for the second time so I have my own hmwk to do.

heh, been there.

 

[COmtbiker12]

.well, i think it goes like this.

there are 52 cards. you only use K,Q,J.
that means only 3 cards from each maze.

total 12 cards from which you can do the combination.
now, the part for you.
what are the combinations you can do with those 12 cards in a 5 card hand?

Lol, I'm a dumbass, I kept trying to use 52 for some reason. Thanks.

 

[COmtbiker12]

Ask your parents......... they should be able to figure it out with the explanation in the book.

-S.S.-

My mom was stumped. And my dad ain't here.

 

[chicodude]

What grade are you in? and I would help but I'm doing calculus for the second time so I have my own hmwk to do.

I guess not everyone can be as smart as you......

 

[caputo1989]

Ok.
4*3=12 12*4=48 for the first one and add 12 for the seccond one

 

[Jou]

Wait till college, my statics teacher is 2 lectures behind the homework. i'd learn how to teach yourself.

 

[-dustin]

your prof must be tenured, or however it's spelled.

 

[COmtbiker12]

Ok.
4*3=12 12*4=48 for the first one and add 12 for the seccond one

How'd you do that?

 

[ALEXIS_DH]

Ok.
4*3=12 12*4=48 for the first one and add 12 for the seccond one

oh, kids these days....

 

[COmtbiker12]

oh, kids these days....

Can you work out the first one? I got 792...

 

[ALEXIS_DH]

Can you work out the first one? I got 792...

and how did you get that?

 

[COmtbiker12]

and how did you get that?

since you have 12 cards, and 5 cards in the hand and the formula for nCr is n!/r!(n-r)! I plugged it in so I had 12!/5!(7!) which i got to be 792..... I dont know.... sounds way too high, lol.

 

[caputo1989]

How'd you do that?

There are 4 of each card in a deck of 52.
There are 3 cards that we are working with.
Multiply 3*4 and get 12
Out of 5 cards in the hand. Multiply the 12*5=60
I was wrong the first time so ignore it I didn't read the problem all the way.
THE ANSWER IS 60. NOT 48.
then there are four aces in a deck so do 4*4=16 and add ti to 60
and get 76.

 

[ALEXIS_DH]

since you have 12 cards, and 5 cards in the hand and the formula for nCr is n!/r!(n-r)! I plugged it in so I had 12!/5!(7!) which i got to be 792..... I dont know.... sounds way too high, lol.

honestly i dont remember...
but if you are sure that is the formula....

 

[WhiteRavenKS]

let us know the answer when you get this back. i seriously am having a hard time believing i got ap credit for stats right now.

 

[Wumpus]

Here is another example:

http://mathforum.org/dr.math/faq/faq.comb.perm.html

 

[COmtbiker12]

Thanks for the site Wumpus.

WhiteRavenKS I'll be sure to post the answer tomorrow afternoon.

 

[Wumpus]

Thanks for the site Wumpus.

Google is a wonderful thing.

 

[T0mo]

crap, you're in 10th grade? I just graduated high school without ever taking anything past geometery...

 

[-dustin]

the lowest grade i got in Alg II was a 98, and ended up with a 99 for the class. i don't remember how to do that.

--edit--

but if you give me the answer tomorrow, i'll come up with a way to find the solution. i like working backwards for some reason.

 

[COmtbiker12]

Google is a wonderful thing.

I'm busy doing other homework. Other than the math (which I've now finished, hopefully correctly) I've got to prepare for an essay for The Great Gatsby and I'm going through the book finding as many examples of symbolism through colors as I can...

 

[Wumpus]

I'm busy doing other homework. Other than the math (which I've now finished, hopefully correctly) I've got to prepare for an essay for The Great Gatsby and I'm going through the book finding as many examples of symbolism through colors as I can...

Google is a wonderful thing. --> http://www.google.com/search?hl=en&q=The+Great+Gatsby+color+symbolisms&spell=1

 

[COmtbiker12]

Google is a wonderful thing. --> http://www.google.com/search?hl=en&q=The+Great+Gatsby+color+symbolisms&spell=1

I already did that earlier. It was just finding the quotes in the book. And despite only needing 6, I've got about 25 possible ones I can use. I guess that's because I usually cut corners and underdevelop my ideas so it'll be a good thing to have backups.

 

[-dustin]

google is crrrrrrrrrazy

http://www.google.com/search?num=100&hl=en&lr=&safe=off&c2coff=1&client=firefox-a&rls=org.mozilla:en-US:official&q=(((5e17+7e12)/9)*32e-19+J*s)+(27eV*(1920s+234s+12e8m/speed+of+light)))+/(speed+of+light)&btnG=Search

 

[mack]

Im in 10th grade and stuck in algebra 2, its so easy, i was going to switch to Trig but they couldnt get me into a honnors class, and i wanted a esay A.

What book do you guys use? Ours sucks pole! the examples really do blow.

 

[COmtbiker12]

uhh, im a math d00d at university... i'll see what I can think of...


first of all you say 'what are the combinations you can have...' this implies you have to list the particular combinations. do you possibly mean 'how many' combinations?

Well, if I go by what you stated 'what are the combinations....' you would just list each possible combination... how had is that?

I meant how many, my bad...

 

[mattv2099]

I meant how many, my bad...

We are looking for a combination of n objects taken r at a time where

nCr = n!/(r!(n-r)!)

example: (str8 outta my probability textbook)

The number of possible five card hands drawn from a deck of 52 cards is

52 C 5 = 52!/(5!47!)




OK. your question is very similar. In fact your question is what is the number of possible five card hands drawn from a deck of 12 playing cards.

12 C 5 = 12!/(5!7!)




got it?

 

[COmtbiker12]

We are looking for a combination of n objects taken r at a time where

nCr = n!/(r!(n-r)!)

example: (str8 outta my probability textbook)

The number of possible five card hands drawn from a deck of 52 cards is

52 C 5 = 52!/(5!47!)




OK. your question is very similar. In fact your question is what is the number of possible five card hands drawn from a deck of 12 playing cards.

12 C 5 = 12!/(5!7!)




got it?

Our book has the example of 52 C 5 as well.... so I did do it right by doing 12 C 5 which is the same as 12!/(5!7!) which gave me 792?

 

[JMAC]

Actaully I sympothys with you, my cal teacher last sem was such a packy. I couldn;t understand anything he said. He started preatching buddhism to us to. So I gave up and never went back to class. Now I have another packy teacher but at least I can understand what she says, and so far so good. But we'll see.

 

[-dustin]

**** profs who are not coherent. that pisses me off so much. that as well as ESL programs for grad students.

 

[caputo1989]

I'm not in algraba 2 im stuck in geometry. It sucks. I hope I got the right answer.
tell us tomarrow

 

[DHGH]

For some reason I want to say its:

12*11*10*9*8

For card one, you have your choice of 12 cards, so you pick one of 12 possibilities.
For the second card, you have your choice of the 11 remaining cards, so 11 more possibilities for each of the preveious 12.
For the third, you have 10 cards remaining to choose from and so on...

That might wind up being the same thing as your factorial equation (might not be...it's late), but I find thinking about it in a step by step fashion makes things clearer rather than just throwing into a general equation. I'm in upper order differential equations right now and those kinds of problems can still get the better of me, but they're still more interesting than this shi*t...