So you've got two grid sheets that contain 100 squares. Each row and column is randomly numbered 0-9. You pick one square on each sheet in different spots. Turns out you've got the same random column and row number on each sheet. What are the odds of that happening? Does my explanation make sense? Pay attention, god dammit.

A simpler explanation is this, for those of you familiar with Super Bowl grid pools: I've got the same numbers in two different pools. Colts 3, Saints 4. Not bad numbers to have. I want to know the odds of getting the same numbers.

So you mean if you pick one number on the first sheet, what are the odds of getting the same number in the same row and column on the second?

In that case, it's 1/1000. You've got a 1/100 chance of picking the same space, and there's a 1/10 chance that the number contained within that space is the same as the one you got the first time. 1/100*1/10=1/1000.

So you mean if you pick one number on the first sheet, what are the odds of getting the same number in the same row and column on the second?

In that case, it's 1/1000. You've got a 1/100 chance of picking the same space, and there's a 1/10 chance that the number contained within that space is the same as the one you got the first time. 1/100*1/10=1/1000.

Right, I was taking the first one not to matter, all you have to do is match it on the second. If you have to hit a specific square on the first one, then match it and the number on the second, odds are 1/100,000. If you have to get a specific number on the first square too, 1/1,000,000.

Right, I was taking the first one not to matter, all you have to do is match it on the second. If you have to hit a specific square on the first one, then match it and the number on the second, odds are 1/100,000. If you have to get a specific number on the first square too, 1/1,000,000.

I am not trying to *match* anything. The squares were completely random. Imagine throwing a dart at two grids, and the numbers get filled in randomly after the fact.

I am not trying to *match* anything. The squares were completely random. Imagine throwing a dart at two grids, and the numbers get filled in randomly after the fact.

For any of the 2 grids, there are 100 unique pairs. So you have a 1/100 chance of getting some random combination (in your case Colts 3-Saints 4). Layout is irrelevant.

Since the 2 boards are independent, you have an equal probability of that particular combination in both boards. Thus,

(1/100)^2 = 1/10,000 = .0001

is the probability of getting the exact same combination...twice.

Yeah, but how are you (or anybody) getting 1/1000?

This is basic probability......

Allow me to reiterate... there are 100 distinct ordered pairs for any board. (1,1),(1,2),(1,3),...,(1,n),...(m,n) for m, n in the set (0,1,...,9)

The chance that you get (3,4) is 1/100 which is the same probability for (4,3).

The two boards are independent. Whatever you got on the first board, doesn't affect the probability of you getting any one of the distinct 100 ordered pairs on the second.

So you've got two grid sheets that contain 100 squares. Each row and column is randomly numbered 0-9. You pick one square on each sheet in different spots. Turns out you've got the same random column and row number on each sheet. What are the odds of that happening? .

the odds to hit the same numbet in row=1/10
the odds to hit the same number in column=1/10
and the odds to hit the same number in row AND column =
1/(10^2)...

For any of the 2 grids, there are 100 unique pairs. So you have a 1/100 chance of getting some random combination (in your case Colts 3-Saints 4). Layout is irrelevant.

Since the 2 boards are independent, you have an equal probability of that particular combination in both boards. Thus,

(1/100)^2 = 1/10,000 = .0001

is the probability of getting the exact same combination...twice.

Seems u R mistaken,
1)you are correct : there are 100 unique pairs for each grid.
2)But!!! after you've chosen pair on 1st grid(the odds of choosing pair 1/1, equal 100%, it doesn't matter what pair you choosing, ) the chance that the pair on 2nd grade will match = 1/100, so the answer is not (1/100)*1(100), but 1*(1/100)

ok yo, so it turns out the WIFE also has Saints 4, Colts 3. Seriously. Soooo...what are the odds now of pulling the same numbers on THREE sheets. LOL...I'm not kidding.

Seems u R mistaken,
1)you are correct : there are 100 unique pairs for each grid. 2)But!!! after you've chosen pair on 1st grid(the odds of choosing pair 1/1, equal 100%, it doesn't matter what pair you choosing, ) the chance that the pair on 2nd grade will match = 1/100, so the answer is not (1/100)*1(100), but 1*(1/100)

ok yo, so it turns out the WIFE also has Saints 4, Colts 3. Seriously. Soooo...what are the odds now of pulling the same numbers on THREE sheets. LOL...I'm not kidding.

Ray,
You'd be right if he was asking the chance of getting colts 3, saints 4 on two of two sheets. He's just asking about the chance of two matching sheets (.01).

Ray,
You'd be right if he was asking the chance of getting colts 3, saints 4 on two of two sheets. He's just asking about the chance of two matching sheets (.01).

So you've got two grid sheets that contain 100 squares. Each row and column is randomly numbered 0-9. You pick one square on each sheet in different spots. Turns out you've got the same random column and row number on each sheet. What are the odds of that happening? Does my explanation make sense? Pay attention, god dammit.

A simpler explanation is this, for those of you familiar with Super Bowl grid pools: I've got the same numbers in two different pools. Colts 3, Saints 4. Not bad numbers to have. I want to know the odds of getting the same numbers.

"Two matching sheets?" I don't see any mention of this in the OP's post. So as far as I'm concerned, I'm right, and just about everybody else has been throwing out garbage excuses for "math".

I interpreted the above in bold as: "What is the probability of picking the pair (3,4) in two independent draws?"

So you've got two grid sheets that contain 100 squares. Each row and column is randomly numbered 0-9. You pick one square on each sheet in different spots. Turns out you've got the same random column and row number on each sheet. What are the odds of that happening? Does my explanation make sense? Pay attention, god dammit.

A simpler explanation is this, for those of you familiar with Super Bowl grid pools: I've got the same numbers in two different pools. Colts 3, Saints 4. Not bad numbers to have. I want to know the odds of getting the same numbers.

The answer to the bolded question is .01. There isn't any reason to think IRB meant (3,4) on two sheets, except for the passing mention of those two numbers in the example (which obviously confused you).

Calpoly doesn't have a grad program EDIT: and you didn't go to grad school anyway.

Man if u have degree in statistics you still should try to think...
To simplify - the question is"what is the chance that pair in 1st table will be the same as pair in 2nd" - you have one event!!!, not two >>>>what is 2nd event man?? where do u see it? or it is in wiki?)))

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